00:01
All right here on this problem, we want to solve the system of equations using gauss, jordan elimination.
00:07
So with our coefficients, we have 1, 2, and 0 up top.
00:12
I have to put in a 0 because we don't have a z term up top, but we do in the bottom.
00:16
And so this is really a 3 by 3 system.
00:20
In the middle we have 1, 4, and 0.
00:24
And on the bottom, we have 2, 0, and 1.
00:28
There's no y term there, and so we have a 0.
00:30
Then the right hand side is negative 3, negative 2, negative 8.
00:42
Let's let row 2 equal the original row 2 minus the original row 1.
00:53
And so i'm not going to do anything with row 1 right now.
00:59
But for row 2, i type 1 minus 1 is 0.
01:02
4 minus 2 is 2.
01:05
0 minus 0 is 0.
01:07
Negative 2 minus negative 3 is 1.
01:13
And then let's just keep row 3 the way it is.
01:16
And so we'll just leave it as 2 -0 -1 -negative 8 just for now...