00:02
So here, we're trying to find out how these compounds would act as an acid when dissolved in water.
00:10
So remember, the broncelauri definition of an acid is basically just a donor of hydrogen cations or protons, whatever you want to call them is fine.
00:26
And a broncelauri base is just a hydrogen cation acceptor.
00:38
So here our first compound, which we're treating as an acid, is h .c .o4.
00:48
And this is dissolved in water.
00:51
Our water is acting as our base.
00:54
And in this reaction equation, we have hclo4 acting as the acid, water acting as a base.
01:04
So hclo4 donates a proton to water, and we get hydronium, h3o plus.
01:12
And then that's our conjugate acid.
01:14
For our conjugate base, we get cl -04 minus due to the loss of the hydrogen cadion.
01:21
For our second compound in part b, we have hc2 -h -3 -o -2.
01:28
That is also dissolved in water...