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Problem 25 Medium Difficulty

Write equations to represent the following observations.
(a) A mixture of $\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})$ and $\mathrm{Zn}(\mathrm{OH})_{2}(\mathrm{s})$ is
treated with $\mathrm{NH}_{3}(\text { aq }) .$ The $\mathrm{Zn}(\mathrm{OH})_{2}$ dissolves, but the $\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})$ is left behind.
(b) When $\mathrm{NaOH}(\mathrm{aq})$ is added to $\mathrm{CuSO}_{4}(\mathrm{aq}),$ a pale blue precipitate forms. If $\mathrm{NH}_{3}(\mathrm{aq})$ is added, the precipitate redissolves, producing a solution with an intense deep blue color. If this deep blue solution is made acidic with $\mathrm{HNO}_{3}(\mathrm{aq}),$ the color is converted back to pale blue.

Answer

$\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2 *}(\mathrm{aq})+4 \mathrm{H}_{3} \mathrm{O}^{*}(\mathrm{aq}) \rightleftharpoons\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2+}(\mathrm{aq}, \text { pale blue })+4 \mathrm{NH}_{4}^{+}(\mathrm{aq})$

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Video Transcript

Hello, everyone. My name is in this simple question. We have here zinc at that You 200 side which is insoluble solid. When we eight ammonia to the solar we found this solid becomes Sola ball because it for missing for pneumonia at that should do to hydroxide which is is is soluble So it's a salable one. Not right like these. All right, Like says Don't forget this because we need salable. It exists normally, you know. Yeah So these e the first far that second war It is longer cover postive toe react with hydroxide. So it formed Kupper Heidrick sign which is Bill Blue Baby T disease Bell blue baby t is insoluble So really three activities for ammonia It will this solve line the previous one to form a copper. I'm on your and two on the sign Which of these one is solid ball and its color is deep. No color then This compound cover in inches tree full Most if toe is reactive is a four of water do for copper for over a tour posted to and for pneumonia exit And the color here is Bill Blue color solely bowl. So USIA Thank you

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