00:02
To draw the lewis structures of the given ions, we first must determine how many valence electrons are present.
00:10
Starting with clo minus, we have seven valence electrons coming from the chlorine, six valence electrons coming from the oxygen, plus one electron coming from the negative charge.
00:25
This leaves us with a total of 14 valence electrons.
00:29
To draw the lewis structure, we start with the atoms, and then begin filling in the electrons.
00:37
So we have a pair of electrons to form that chemical bond between the two atoms.
00:41
And with the remaining 12 electrons, we can add three alone pairs onto each atom.
00:50
So that we have a full octet on the chlorine, a full octet on the oxygen, and a single bond between the two.
01:01
The final step is to draw brackets and a negative sign to indicate that this is an ion.
01:07
We can do the same thing for sncl3 minus, where we begin with four valence electrons coming from 10 plus 7 from chlorine, multiply that by 3, and then add one electron for the negative charge...