00:02
So the first loose structure we'll be doing is the bond between chloride and chlorine.
00:09
And we know there's 14 valence electrons since both atoms have 7.
00:14
So i see that would be 14.
00:18
So there's your bond, which of course will count as 2.
00:22
So now we just have 12 left.
00:23
So 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.
00:31
So there is your answer for part a.
00:34
Now we have some name dioidhydride.
00:38
This would hold eight valence electrons.
00:42
And some one needs to be in the middle since hydrogen can just hold that bond.
00:48
So right there, that's four.
00:50
And then we'll put our two extra electrons there because they can't go on the hydrogen since they're already equal.
00:58
So that is your answer for part b.
01:01
C, we have boron chloride fluoride, and we have 24 valetriolide...