00:01
Problem 105 says to draw the lewis structure that obeys the octet rule for each of the following.
00:06
So the first is a central phosphorus bound to an oxygen, a chlorine on each of the remaining sides.
00:26
So because the central phosphorus already has its octet rule to obeyed, meaning that it has eight surrounding electrons, the remaining electrons of the 32 here, five from phosphorus, six from oxygen, making 11, and then an additional 21 from these seven each from chlorine.
00:51
Each of those remaining electrons has to go around the oxygen and chlorines.
01:01
So in total here we have eight electrons surrounding each of these atoms.
01:07
Atoms, meaning that each of the atoms obeys the octet rule, and this is the appropriate structure.
01:15
The problem also says to tell the formal charges of each of the central atoms.
01:19
And so in this case, because phosphorus in its atomic form has five valence electrons, and we only have four valence electrons here, the central atom has a positive one charge.
01:34
So next we have the sulfate ion, which is a central sulfur.
01:39
Surrounded by four oxygens.
01:48
And so because, again, this central sulfur here already obeys the octet rule, the remaining of the 32 electrons here has to surround each of these oxygens.
02:19
So in this case, because, like i said, the central, i don't think i said it, sorry, the central sulfur, typically like oxygen, has six valence electrons.
02:31
It's essentially too short here, meaning that has a positive two formal charge.
02:39
Now, the negative to ionic charge here comes from the fact that each of these oxygens, having seven valence electrons instead of six, has sort of one extra, making each of the surrounding oxygens have a negative one formal charge.
02:55
And so it's interesting about the remaining molecules that you see on this screen, or ions and molecules that you see on this screen, are that the general structures that each of them is the same.
03:18
So for the perchlorate ion here, you have essential chlorine surrounded by four oxygens, the valence around each of the oxygens is three lone pairs...