00:02
So write net ionic equations for the reactions listed in problem 4 .69.
00:09
For a, we have s8 gas and 802 gas to produce 8 s .o2 gas.
00:24
There's no aqueous species.
00:27
So this would be our net ionic equation.
00:30
There would be no spectators.
00:31
So there's our equation right away.
00:32
For b, we've got nickel to chloride, aqueous, sodium sulfide, and this would produce nickel to sulfide.
00:49
That's a solid and 2nacl aqueous.
00:53
Let's break apart our acrease species.
00:55
This gives us 2 plus, cl minus, 2na plus, that's 2 minus, sulfide solid, 2n2, cl minus.
01:15
Cancelot our spectators, 2na plus, 2cl minus...