00:01
Okay, so in this question, they said that an hypothetical element was with an atomic number of 118 and weight of 293.
00:09
So we just call that element e is formed when lead 208.
00:17
So 2 .08 is bombarded with krypton 86.
00:22
So the first thing we do is we find the number of protons that lead and krypton have.
00:27
So when we look at the periodic table, we see that lead is element number 82.
00:33
82 protons and krypton is element number 36 so it's 36 protons.
00:38
Now let's balance out the protons.
00:40
So we have 82 plus 36 on the left side.
00:44
This forms 118 and on the left side we see on the right side we see that there's also 118.
00:49
So protons are balanced now let's look at the weight.
00:52
We have 208 plus 86.
00:54
This gives us 294 but we only have 293 on the right side.
00:59
So in order to balance it out, all you do is add a nitrogen.
01:04
Keeps our proton balance because there's zero proton added on.
01:07
And this keeps our weight balance because we added one to the 293 to make 294.
01:13
And then the next step, they said that this hypothetical element undergoes alpha decay...