We do this by substituting the values of $n$ from 1 to 5 into the sequence.
For $n=1$, we have $\sqrt{1^{2}+3 \cdot 1}-1 = 1$.
For $n=2$, we have $\sqrt{2^{2}+3 \cdot 2}-2 \approx 1.162$.
For $n=3$, we have $\sqrt{3^{2}+3 \cdot 3}-3 \approx 1.2426407$.
For
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