Question
Write plausible Lewis structures for the following odd-electron species: (a) $\mathrm{CH}_{3} ;$ (b) $\mathrm{ClO}_{2} ;$ (c) $\mathrm{NO}_{3}$.
Step 1
(a) CH₃: - Carbon (C) has 4 valence electrons. - Each hydrogen (H) has 1 valence electron, and there are 3 hydrogens. - Total valence electrons = 4 (C) + 3 × 1 (H) = 7 electrons. (b) ClO₂: - Chlorine (Cl) has 7 valence electrons. - Each oxygen (O) has 6 valence Show more…
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