Write reactions for which the enthalpy change will be a. ΔHf^∘ for solid aluminum oxide. b. The

Write reactions for which the enthalpy change will be a....

Write reactions for which the enthalpy change will be a. $\Delta H_{\mathrm{f}}^{\circ}$ for solid aluminum oxide. b. The standard enthalpy of combustion of liquid ethanol, $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l) .$ c. The standard enthalpy of neutralization of sodium hydroxide solution by hydrochloric acid. d. $\Delta H_{\mathrm{f}}^{\circ}$ for gaseous vinyl chloride, $\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}(g)$. e. The enthalpy of combustion of liquid benzene, $\mathrm{C}_{6} \mathrm{H}_{6}(l)$. f. The enthalpy of solution of solid ammonium bromide.

Write reactions for which the enthalpy change will be
a. $\Delta H_{\mathrm{f}}^{\circ}$ for solid aluminum oxide.
b. The standard enthalpy of combustion of liquid ethanol, $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l) .$
c. The standard enthalpy of neutralization of sodium hydroxide solution by hydrochloric acid.
d. $\Delta H_{\mathrm{f}}^{\circ}$ for gaseous vinyl chloride, $\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}(g)$.
e. The enthalpy of combustion of liquid benzene, $\mathrm{C}_{6} \mathrm{H}_{6}(l)$.
f. The enthalpy of solution of solid ammonium bromide.

Key Concepts

Enthalpy of Solution

The enthalpy of solution describes the heat change that occurs when a solid or other solute dissolves in a solvent. This process involves breaking solute-solute interactions and forming new solute-solvent interactions, making it a central concept in understanding dissolution and solution chemistry.

Standard Enthalpy of Formation

This concept refers to the enthalpy change when one mole of a compound is formed from its elements in their most stable forms under standard conditions. It is a fundamental idea in thermochemistry as it provides a baseline for calculating the enthalpy changes of other reactions.

Standard Enthalpy of Combustion

The standard enthalpy of combustion is the heat released when one mole of a substance burns completely in oxygen under standard conditions to yield common combustion products, typically CO2 and H2O. This concept is essential for understanding energy changes in fuel burning and related reactions.

Standard Enthalpy of Neutralization

This is the enthalpy change associated with the neutralization reaction between an acid and a base, where typically one mole of water is produced under standard conditions. It serves as a key measure in acid-base thermodynamics and is usually exothermic for strong acids and bases.

Transcript

00:01 This question is asking us to set up reactions for the in therapy changes or the delta h changes.

00:08 And we have a siri's of about five or six reactions that we need to look at now.

00:13 Basically, we're just sort of going back to putting together general equations.

00:20 We just have to keep in mind that the substance in question, but needs it turn out to be one mole.

00:25 So when you balance the equation, sometimes you'll have more than one mole.

00:29 You just make sure and even out.

00:31 So it's only in terms of one more of that product.

00:34 So, for instance, we're gonna set up the balanced equation for when we combine aluminum with oxygen and we'll get aluminum oxide.

00:53 It's aluminum oxide.

00:55 That formula for that is a ll three l three owed to can't seem to write a three today.

01:05 Oh, too, there you go.

01:08 So in order to balance is out, we would need hey actually able to 03 here we go.

01:31 All right, so in order to balance it out, we're gonna go ahead, and, uh, we'll need to put it to here in front of the aluminum oxide and ah, that will balance out.

01:45 You give the oxygen's and even number over here.

01:48 I'll have to put three three miles of oxygen, only four overall of aluminum.

01:55 Now, what we have to do is i need this to be a wood over here.

02:00 This seems to be a coefficient of one.

02:02 So i needed to find everybody by 1/2.

02:05 So we're gonna have to most of aluminum 1.5 or three moles of 02 and then we'll have our one mole of aluminum oxide.

02:23 So that's what they're looking for.

02:24 And this is basically they don't give us adult age values.

02:27 So i'm not sure what to you know what? we're to put it on the left or the right or what the value is, but that's what that reaction would look like.

02:35 That's, um, the in therapy reaction formation for aluminum oxide.

02:41 Now we have a few more to go through, but the just is generally the same.

02:46 So we have liquid ethanol.

02:48 Liquid ethanol is c two.

02:56 Let me see too.

02:59 Age five.

03:02 Ohh, yeah, yeah, let's see to h 50 age, and we'll burn that in the presence of three oxygen's.

03:11 I went ahead and balances out already.

03:13 And it turns out we don't need to manipulate that coefficient in front of methanol or ethanol.

03:19 So we're going to go see you, too.

03:24 And we'll also have three waters.

03:27 Okay, so i did not need to put any sort of coefficient in front of that.