00:01
In this question, let's look at the resonance structures for these.
00:03
So the first one is selenium dioxide.
00:06
First of all, we'll calculate the number of valance electrons, and we do that by looking at the group number.
00:11
All these are group six.
00:13
There are three atoms.
00:14
Three times six is 18.
00:15
So therefore, there should be 18 valence electrons.
00:18
When we draw the loose structure, this is what it ends up looking like.
00:21
Then we can see that there's just resonance in between these two double bonded oxygens, and these are the resonance structures.
00:29
So when you see two doubly bonded oxygen to the same atom, usually that is the place where the resonance will take place.
00:39
Basically, the oxygens will just exchange double bond.
00:42
It's not going to change the number of advanced electrons.
00:44
So let's take a look at nitrate.
00:46
So nitrate is another example where the resonance occurs between the oxygen bonds.
00:51
So basically, when we do the calculation, we end up with the number of valance electrons...