write-the-balanced-chemical-equation-describing-the-dissolving-of-each-of-the-following-sparingly-so

Question

Write the balanced chemical equation describing the dissolving of each of the following sparingly soluble
salts in water. Write the expression for $K_{	ext { sp }}$ for each process.
$\begin{array}{ll}{	ext { a. } \operatorname{Bi}_{2} S_{3}(s)} & {	ext { c. } \operatorname{Co}(\mathrm{OH})_{3}(s)} \ {	ext { b. } \mathrm{Ca}(\mathrm{OH})_{2}(s)} & {	ext { d. } \mathrm{Cu}_{2} \mathrm{S}(s)}\end{array}$

Anatole Borisov · Accepted Answer

so this question were given various solids and were asked to write the equilibrium. Um, that describes their, uh, dissolving in water and figure out Caspian. So our 1st 1 is business, Uh, sulphide. So be I to asked. Three, which is in solid form and will be in equilibrium with business three plus and sulphur to minus. Now, don&#x27;t forget the coefficients. We have three software that you can see from here and to business, and so that&#x27;s going to make sure that the eye of the charges cancel out. And so KSB is equal to the concentration of the products over the concentration reactions. But we have a solid here on. Let me be clear. Here we have a quist ions. That&#x27;s how I was always our unless that ridiculously high temperature eso solids are not considered solid liquid, they&#x27;re not considered the mass action expression. So well, we&#x27;re gonna have us the concentration of business three plus squared. You remember coefficients will become exponential, and then we have solved for two minus cube, and so that&#x27;s gonna be our 1st 1st expression. Next one is calcium hydroxide. I&#x27;ll do that a different color. We have calcium times with 20 h groups. And so that&#x27;s going to be solid again after the storm and ignore the states because it&#x27;s always the same. We have the well. Both ions are Equus, the initial solid solid. And then we have O H minus. But we have two of them. Don&#x27;t forget. Or else you&#x27;re gonna mess up your KSB by forgetting this exponential appear. And so now that&#x27;s our equation. KSB then is going to be equal to the concentration of see a two plus times a constellation of hydroxide just taking the product of all the product products, multiplying all the contractors of the products and ignoring this solid. But remember, there&#x27;s a to further coefficient, so this must be square. Excellent, that sarcastic. Now we have cobalt. I drop side CEO Oh, age three, Big nor the States. For now, until we have Cobalt three. Plus, that&#x27;s a curious, and we have three hydroxide. Know that the charge Cancel out three plus here, plus three one minus is there so no cautious. That&#x27;s ugly. Um And so now we read our Casspi, which is going to be the product of the concentration of the cobalt ion times a constellation of the hydroxide ion to the third power. Don&#x27;t forget that. Three gonna be really sad if you dio. And now we have copper sulphide. See you to us, which is again salir when it dissolves is going to give us copper two plus heart of the knowns. Give us copper Plus and two of them and Saul for two miles. So I&#x27;m gonna take a there to explain the one of the ways you can avoid this sort of mistakes. First off, it&#x27;s useful just to know what common oxidation states we have. Sulphur is basically always two minds. And so if we have two minus here, we know that we have to have two plus in our to neutral tries to stars. We have a total of two plus, but we have to ions here. And so each of these we want Plus, since our ksb those going through the product a C U plus to power of two, because the coefficient there times a concentration of us to minus the sulfide down. That&#x27;s our answer.

Anatole Borisov · Answer

in this problem were given various solids and were asked to show their equilibrium of them dissolving in water and then determine what the cast is. So we have First, we have silver by a date, which the can I on is silver plus. So there&#x27;s gonna be any quibble with a G. Crosse a Prius and I owe three minus saw agrees to um, actually, I&#x27;ll just make the no Now, this first thing is always gonna be solid. The two ions to dissociate into our quest ions are always a Chris on dso or they&#x27;re, like, ridiculously high anyways, So I&#x27;m gonna ignore the states at From here on out. This are equilibrium that we&#x27;re dealing with. No, the equilibrium here and now our Caspi is always products overreacting. It&#x27;s but we ignore solids, elected liquids. And so there&#x27;s really no reactions that we&#x27;re gonna consider. This is a solid nuts are only reacting. So we&#x27;re gonna get the product of the concentration of a G plus times a concentration of I a date. I&#x27;ll three miles. That&#x27;s our answer. Such caused next one, we have 10 hydroxide, and so this is gonna be in equilibrium with 10 to plus note that since each hydroxide on is minus one and this has a neutral charge, as all solids do the 10 house have a two plus charge to counter. Act that, and we have 20 H. Miles. And so Casey&#x27;s gonna be similar. But there&#x27;s an important distinction you can&#x27;t forget. Remember, if you have a coefficient in the equation that&#x27;s going to end up being up, uh, exponential in the in our KSB expression. So we saw the concentration of sn two pots, but here we have the consolation of O. H minus square, and that&#x27;s that&#x27;s something you can&#x27;t forget on this. Gonna be coming up often in these Caspi problems. Now, that&#x27;s probably the most like, difficult thing in the sense that that&#x27;s what people forget. And so our next one is that we have zinc phosphates of three sinks and Keogh for two of them, they&#x27;re gonna be an equilibrium. Zinc is always a two plus charge where we can see by this coefficient there, and phosphate is always a three minus charge. And so, um, now I skipped something here. I didn&#x27;t put the coefficients of front vesting. You just certainly don&#x27;t want to forget. We have three sinks, as we can see here and to phosphates. And so the TSB is gonna be equal to the concentration of zinc two plus to the third. Don&#x27;t forget that times the concentration of phosphate fuel for three minus squared. Don&#x27;t forget that. And finally, we have one more. Um and this really won&#x27;t present anything. We have barium fluoride, B A F two, which will be in equipment with very M two plus. That&#x27;s how barium always is and fluoride minus two of them. Um, you can check your work by noting that we have to flow. Raj, we have to Florence on this side and note that the charges should cancel out. And so K SP is gonna be able to the concentration of barium two plus no exponential. It&#x27;s It&#x27;s to the first power because we technically no one there, but ignore that we have times a concentration of fluoride minus squared, and that is our answer

Shanie Holman · Answer

in this video, we&#x27;re going to practice finding Souljah bility products. So for this 1st 1 set up a balanced equations we&#x27;ve got in, let&#x27;s go ahead and keep the color scheme. What&#x27;s? And I Yes, solid would be an equilibrium with if we add water, um, with the ions. And I lost our color scheme again. Um, and I and that&#x27;s gonna be two plus waas Yes, to minus. These are both dissolved. So now they&#x27;re aw qui iss and our solid building. So you ability expression r k s P is just the concentrations of those two ions. The challenge of changing colors, applause actually know. Plus there all right, just multiplied by plus two minus. And that would be our Celje bility expression for that 1st 1 No exponents because there&#x27;s no coefficients And the n i s the solid doesn&#x27;t figure into the cell you ability product because it&#x27;s a solid and it basically has a concentration off one if you want to look at it that way So let&#x27;s do the 2nd 1 See? You see 03 solid with water at in good would give us copper is a two plus waas c 03 is all one eye on. And that&#x27;s a tu minus. And both loves are dissolved. So again, aqua yous and our Celje bility expression looks much like the one of above. Only with see you two plus and see. Oh, free tu minus the third long, Very young. Okay. C o r 04 Sahlin in equilibrium with again with the addition of liquid water gives us they seem to be on a theme here. Barium is again. And go ahead, make this charge in black just because off the molecular ion for the other one, just to distinguish here. Ah, see, our 04 is a to Linus. You know the way we could do that, it would be to put parentheses around our island. It and these are again aqua yous. Yes, that is a que a que and our equilibrium expression should be starting to look familiar. Los and four, two years just barely sitting on screen there. Okay, one more. This one gets a little more interesting. I&#x27;m gonna move it off to the left. You&#x27;re just a little bit to give myself some more space. We&#x27;ve got a G three and he 04 with the addition of water. Click gives us free a she plus islands and let&#x27;s stick with the theme we had going before and do that in black. A three g plus ions waas, the P 04 ion and that is three minus. These will again be awkwardness and our equilibrium expression. We got the concentration of a G this time with an exponents. Three because of the coefficient and he 04 pre minus. Let&#x27;s clean that she off a little bit. Okay, so that&#x27;s how you set up soluble bility products for the dissolution of ionic solids in liquid water.

Shanie Holman · Answer

in this video, we&#x27;re going to practice setting out soluble ity products. Uh, okay, So for this 1st 1 for the balanced equation, we&#x27;ve got P b. The are too solid, put in liquid water and we get dissociation. So we&#x27;ve got he be and that&#x27;s a two plus obvious. And then we&#x27;ve got to B r. That&#x27;s a minus obvious so that our Celje bility expression is the concentration of P B. No exponents, because there&#x27;s no coefficient on that one. You should probably keep the two plus in there. Yeah, let&#x27;s try that again. Maybe give myself some space two plus and then b R minus, and that one&#x27;s going to have an exponents on it because off the co vision, the PB B r to the solid does not figure into the soluble ity product. You can put an S P on this, indicate that it&#x27;s a soluble ity product because it&#x27;s a solid and pure substances don&#x27;t figure in to equal every, uh, Constance, do you? The 2nd 1 Let&#x27;s take a look at this one. We&#x27;ve got a G two s solid dissolving it in water and we get right to to a G with a plus on that obvious plus so far it&#x27;s changed the color on that sulfur like it&#x27;s where I said, Change color. There we go. So far Tu minus again. Aw quis and are soluble illit e product here going to be the concentration of a G waas raised to the second power because of the coefficient. And then, yes, tu minus and we&#x27;re going to go on that one. Let&#x27;s take a look at the 3rd 1 This one&#x27;s a little more complicated, so we know that we&#x27;ve got PD e oh, free Saul in dissolved in liquid water and we&#x27;re gonna get he be two plus and parentheses around this one. See, oh, three tu minus. So that are soluble ity Product is the concentration of mm, the two plus and see 03 Tu minus. No cough. No exponents on either one of those because there&#x27;s no coefficients. And finally, this last one&#x27;s fairly complicated. Let&#x27;s take a look he&#x27;s got Yes, our should be strong tea on unless I miss my guess. Three. He Oh, for And there&#x27;s two of those that&#x27;s a solid in liquid water. And that will give us three strong Thiam Adams and they have a to that two plus charge. Get My awkwardness is in there and p o for those two of those. Did you meet 04 and that I Ahm has a three minus and is again aqua yous. So that gonna move this down here? Hey, sp, for this one is the concentration of S r two plus raised to the third power because of the coefficient times the concentration of the p 04 phosphate I on and that&#x27;s going to be raised to the second power. And let&#x27;s make sure we got the three minus hiding in there somewhere. So that&#x27;s how you set up the balance equations for and calculate the soluble ity products for dissolving ionic solids, these ionic solids in water.

Lena Jake · Answer

Okay, So in this video, we&#x27;re going to answer a question 86 from chapter 17 which says to write balanced equations and expressions for the ke sp for the dissolution of each ionic compound. So the first thing we have is calcium carbonate. Um, so are solid C A, C 03 associates into a Prius C I plus two ions in a curious CEO three minus two. I arms. And for a case, be all we need to write our products divided by reactant excluding are solid reactant. So we have just our concentration of see a plus two times our concentration of seo three minus two. The second compound we have is PV seal to soapy. Be seal to, um, and it&#x27;s solid formed associates into P B plus two. That&#x27;s a curious and two chloride ions that are a curious. So we have two chloride ions for every Pete TV seal, too. Um, so we need that streaking metric coefficient there, and it changes our KSB expression. So our KSB expression is again products divided by reactant, but exclude the solids. So we have P V plus two time seal minus squared where the squared comes from our striking metric coefficient of two. Finally, and see, we have a g i so solid a g I&#x27;d associates into a curious Eiji. Plus, in a quiz a minus in rk s p is just, um, our angriest products. So we have a G times I

Aadit Sharma · Answer

So, starting with part, eh? The association reaction will be aging Sito, which three or two will dissociate in a G positive plus C toe edge three or too negative, while the sole ability expression will be okay. Sp for scalability expression Eiji bore the tube plus C two h three or two. Negative, but be the dissociation. Reaction is yeah. Who? H three a l three Sorry. Three Positive Plus three Which negative on the sole ability. Yeah, and the scalability expression will be equal to concentration off he&#x27;ll three positive multiplied with the concentration off. Which negative line race to the power. Three. Because we have three molecules off which moving towards part, see the association reaction will be See a three B O for two. Three c a toe positive plus two people for three negative on the scalability. Expression will be equal to concentration off calcium multiplied with the concentration off P o for three negative raised to the power to because we have to molecules off p o for three negative

Problem

$K_{\mathrm{sp}}$ for copper(II) hydroxide, $\mat…

Problem 58 Hard Difficulty

Answer

a. $K_{s p}=\left[B i^{3+}\right]^{2}\left[S^{2-}\right]^{3}$
b. $K_{s p}=\left[C a^{2+}\right]\left[O H^{-}\right]^{2}$
c. $K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$
d. $K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

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Introductory Chemistry

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Stephanie C.

Lizabeth T.

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a. $K_{s p}=\left[B i^{3+}\right]^{2}\left[S^{2-}\right]^{3}$b. $K_{s p}=\left[C a^{2+}\right]\left[O H^{-}\right]^{2}$c. $K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$d. $K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

Introductory Chemistry

Theodore D.

Stephanie C.

Lizabeth T.

Morgan S.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

Theodore D.

Stephanie C.

Lizabeth T.

Morgan S.

a. $K_{s p}=\left[B i^{3+}\right]^{2}\left[S^{2-}\right]^{3}$
b. $K_{s p}=\left[C a^{2+}\right]\left[O H^{-}\right]^{2}$
c. $K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$
d. $K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

Steven S. Zumdahl, Donald J. DeCoste

Introductory Chemistry