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Write the balanced nuclear equation for the production of the following transuranium elements: (a) berkelium-244, made by the reaction of Am-241 and He-4(b) fermium-254, made by the reaction of Pu-239 with a large number of neutrons(c) lawrencium-257, made by the reaction of Cf-250 and B-11(d) dubnium-260, made by the reaction of Cf-249 and N-15
a) $_{95}^{241} \mathrm{Am}+_{2}^{4} \mathrm{He} \rightarrow_{97}^{244} \mathrm{Bk}+_{0}^{1} \mathrm{n}$b) $_{94}^{239} \mathrm{Pu}+15_{0}^{1} \mathrm{n} \rightarrow_{100}^{254} \mathrm{Fm}+6_{-1}^{0} \mathrm{e}$c) $_{98}^{250} \mathrm{Cf}+_{5}^{11} \mathrm{B} \rightarrow_{103}^{257} \mathrm{Lr}+4_{0}^{1} \mathrm{n}$d) $_{98}^{249} \mathrm{Cf}+_{7}^{15} \mathrm{N} \rightarrow_{105}^{260} \mathrm{Db}+4_{0}^{1} \mathrm{n}$
Chemistry 102
Chapter 21
Nuclear Chemistry
Carleton College
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I've won. This is Ricky. And today we're working on Robin for seven. And so this question, we're just gonna be going through a few balanced nuclear reactor equations. All right, So we have American to 41 and it's made by fusion American and William. We're in alpha particle to make Callie, um, plus a neutron. Next up, we, uh, Tony, um 2 39 which has been bartered with neutrons to make for me. Um, 2 54 Not make sure that everything is balanced. Too cumbersome. Sort of two K that lead to the release of six electrons. Next, we have CF 2 50 So how about that? Cf 2 50? Racking with four on 11 to make Lauren soon with some neutrons left over. And then, lastly for the night, see 7 to 49 plus ranches and 15 Well, May dubbed me. Um, 2 60 and four neutrons of city
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