00:01
So now we're on problem 66 from chapter 8, where they ask us to write the electron configuration for each ion that we're given.
00:10
So we can go ahead and start with the first one, where we have chlorine and chlorine minus.
00:22
So to write the electronic configuration, we look at chlorine, where it is on the periodic table, and recognize that it's going to have gain one electron.
00:33
And by gaining one electron, it will give it noble gas configuration.
00:37
So the electronic configuration for chlorine is simply the electronic configuration for argon.
00:48
In part b, we're given phosphorus 3 minus.
00:54
Now phosphorus is two spaces before chlorine.
01:00
So if we gain three electrons for phosphorus, it will also have the electronic configuration of argon.
01:11
In part c, we're given potassium.
01:12
Plus.
01:15
So potassium is a row below chlorine and phosphorus, but if we lose one electron, we can see that the element before potassium in the periodic table is argon...