Question
Write the equation for roasting iron pyrite in the absence of air to form elemental sulfur. Calculate the volume of $\mathrm{S}_{2}$ gas that can be produced from roasting $5.5 \mathrm{~kg}$ of iron pyrite. Assume that all of the sulfur in the iron pyrite is converted to $\mathrm{S}_{2}$ gas. (Assume STP to calculate the gas volume.)
Step 1
Iron pyrite is FeS₂. When roasted in the absence of air, it decomposes to form iron and sulfur gas (S₂). The balanced chemical equation for this reaction is: \[ \text{FeS}_2 \rightarrow \text{Fe} + \text{S}_2 \] Show more…
Show all steps
Your feedback will help us improve your experience
Prashant Bana and 70 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
what volume of sulfur dioxide at 25c and 1 atm pressure is produced when one boxcarload (4 x 10 ^3 cu.ft) of chalcopyrite ore (density = 2.6 g/cu.cm) is roasted? assume all the sulfur in the ore is converted to so2 and no other source of sulfur is present
Calculate the amount of sulfur dioxide produced when 72.6 grams of iron pyrite (FeS2) completely reacts with oxygen according to the equation: 4 FeS2 + 11 O2 2 Fe2O3 + 8 SO2
Write the equation for the roasting of lead sulfide. What volume of $\mathrm{SO}_{2}$ gas measured at standard temperature and pressure is produced from the roasting of $1.0 \times 10^{2} \mathrm{~g}$ lead sulfide?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD