Write the equation for the final step in the β-oxidation pathway of any fatty acid with an even

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Write the equation for the final step in the β-oxidation...

Key Concepts

?-oxidation pathway

?-oxidation is a metabolic process that breaks down fatty acids into acetyl-CoA units through a cycle of reactions including dehydrogenation, hydration, oxidation, and thiolysis. Each cycle shortens the fatty acyl-CoA molecule by two carbon atoms and produces reducing equivalents in the form of NADH and FADH2, which are subsequently used in the electron transport chain for ATP generation.

Thiolysis

Thiolysis is the step in the ?-oxidation cycle where ?-ketoacyl-CoA is cleaved by the enzyme ?-ketothiolase. This reaction involves the addition of coenzyme A, which attacks the carbonyl group, leading to the splitting of the acyl chain into a molecule of acetyl-CoA and a fatty acyl-CoA that is two carbons shorter than the original. In the final cycle for an even-numbered fatty acid, thiolysis results in the formation of two molecules of acetyl-CoA.

Acetyl-CoA

Acetyl-CoA is a central metabolic intermediate that plays a critical role in energy production and biosynthetic pathways. In the context of fatty acid oxidation, acetyl-CoA produced through successive cycles of ?-oxidation enters the citric acid cycle (Krebs cycle) to generate ATP, or it can be used for the synthesis of other compounds. Its formation marks the key connection between fatty acid catabolism and the central energy metabolism.

Even-numbered fatty acid metabolism

Odd- and even-numbered fatty acids are metabolized differently in ?-oxidation. For fatty acids with an even number of carbon atoms, the degradation process continues until the remaining acyl-CoA molecule is four carbons long, at which point thiolysis cleaves it into two acetyl-CoA molecules. This final reaction is crucial because it completes the oxidation of the fatty acid, ensuring that all carbons from the molecule are effectively converted into metabolic energy.

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