Question
write the equations of the tangent and normal at the given point. Check some by calculator.$$y=3 x^{2}-1 \quad \text { at } x=2$$
Step 1
Given the function \( y = 3x^2 - 1 \) and the point at \( x = 2 \), substitute \( x = 2 \) into the function to find \( y \). \[ y = 3(2)^2 - 1 = 3 \times 4 - 1 = 12 - 1 = 11 \] So, the point of interest is \( (2, 11) \). Show more…
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