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Write the first four terms of each binomial expan…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42

Problem 27 Hard Difficulty

Write the first four terms of each binomial expansion. See Examples 4 and $5 .$
$$
(r+2 s)^{12}
$$

Answer

$r^{12}+24 r^{11} s+264 r^{10} s^{2}+1760 r^{9} s^{3}$

Related Courses

Precalculus

Beginning and Intermediate Algebra

Chapter 14

Sequences and Series

Section 4

The Binomial Theorem

Related Topics

Introduction to Sequences and Series

Introduction to Combinatorics and Probability

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Watch More Solved Questions in Chapter 14

Problem 1

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Problem 4

Problem 5

Problem 6

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Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

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Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Video Transcript

Okay, so we want to write our 1st 4 turns. So let's start with the first time that's going to be 14. Choose zero and an R to the power of 14 Tutsis or through our fortune and then or a second term that would be a 14. Choose one our to the power of 13 and then to us to the part of one. So what's 14? Choose one That's a 14 times a to which is 28 are 13 and anus. And then in order term we have a 14. Choose to are 12 and to us to part of two. So what's 14? Choose two. That's a 91 of times for so that's 364 or 12 and that's squared. And then Or fourth term, that's going to be 14. Choose three or 11 and then two s cute. So what's Fortune 14? Choose three. That's a 364 times two to the power of three. So yes, a 2912 Our love in and s cute

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Margaret L. Lial , John Hornsby

Beginning and Intermediate Algebra

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Related Topics

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