00:01
We are given here a list of compound names, and we need to write the formula out of the name, and we need to determine which one is an ionic compound.
00:18
So the first one is a compound named sodium hypochlorite.
00:28
If it is sodium hypochlorite, you write n .a., symbol of sodium.
00:33
And then the hypochlorite group is c -l -o.
00:42
C -l -o has a, is an anion with a charge of negative 1.
00:48
Sodium, positive 1.
00:51
It's a cation.
00:53
Therefore, a cation and anion form anionicompion.
01:03
Next, bottom tri -iodide.
01:07
Volume and then iodide three times tri -iodide because they both are non -metals this is non -ionic next aluminum perchlorate aluminum and then perchlorate the formula of the perchlorate group is the perchlorid group cl4 has a negative one charge aluminum is a metal from group three that has that is able to form a cation with a charge of positive three therefore we need to compensate for these three positive charges by having three per clodid groups now we're going to have three negative charges because per clodid is an anion and aluminum is a metal that can form cations this is an anionic compound next calcium acetate, calcium, and then the acetate group, which is ch3, c -o -o.
02:35
The acetate group is an anion that bears a negative 1 charge.
02:41
Calcium is a metal from group 2, which is able to form cation with a charge of positive 2.
02:49
Therefore, we need two negative charges.
02:51
And that's why we want to have two acetate groups per calcium.
02:58
Because calcium is a cation, and acetate is an anion.
03:02
This is anionic compound.
03:10
Next, potassium permanganate.
03:13
Potassium, and then the permanganate group is mn -o -4.
03:20
The permanganate group is an anion with a negative 1 charge...