00:01
So now we'll work on problem 44.
00:06
This problem where has to write the orbital diagram for each element.
00:14
We're given sulfur, calcium, neon, and helium.
00:20
Start with sulfur.
00:26
So for sulfur, the orbital diagram is going to be similar to the electronic configuration, except we're going to write out the electron for each orbital and represent it as an up or down arrow.
00:37
So we have two electrons in the 1s.
00:43
In the 2s, we also have two electrons.
00:47
Then we have 2p, where we have 6 electrons.
00:52
So we want to write three pairs of electrons.
00:59
And then the 3s, we have two electrons.
01:08
Now here's where the orbital diagrams can get a little more tricky.
01:15
And we have to remember huns rule.
01:17
So in the 3p orbital, we have four electrons for sulfur because we can see that it's in that position on the periodic table right below oxygen.
01:30
So the question is, how do we fill in the electrons? so hun's rule tells us that we fill in all orbitals singly first.
01:40
So we first put in three parallel spins and then we put in the fourth electron.
01:48
So if we were to write something like this, for four electrons, that would be incorrect...