00:01
Here we've got some scenarios where we do not follow the octet rule, so we're going to be drawing some lewist structures.
00:06
Boron, when it's involved, often doesn't follow the octet rule because it only makes three bonds.
00:13
So boron often makes only three bonds.
00:17
So in this case, boron's the central atom.
00:19
Chlorine is a halogen.
00:20
Tends to make a single bond, so it makes sense that we can show chlorine bonded to boron this way and fill out the remaining non -bondy electrons on the chlorine.
00:30
This uses all the available electrons, and boron is left with only six electrons, which is common in this atom.
00:40
N -o -2, sometimes compounds contain any nitrogen or any atom in that group might not follow the octet rule because it'll have an odd number of electrons.
00:51
Nitrogen only brings five electrons to the table, so i'm only going to have five electrons to work with.
00:57
So i'm going to be a little bit more careful here.
01:02
Nitrogen, i'm going to have five electrons.
01:05
For the two oxygens, i'm going to have 12 electrons available.
01:08
So total i have 17 electrons to work with in this compound.
01:14
So the way i'm going to set it up, i'm going to write nitrogen as my central atom connected to oxygens...