00:01
In this question, it says, write the lewis structure for each species with the skeleton structure shown below.
00:09
So we have a skeleton structure and we are going to minimize the formal charges and also satisfy the requirements for valence for the atoms.
00:21
So for a, we cannot form any double bonds because boron cannot expand its valence.
00:29
It's already at its maximum valence.
00:31
So the lewis structure will just be the same as the skeletal structure.
00:35
We just need to add in the lone pairs of electrons on the fluorines so that they have eight electrons around each.
00:44
So for b, we're going to form a double bond between these carbons to satisfy the requirement for valence because they all need to have a valence of four bonds attached to each carbon.
00:57
And then for this one, we need to double bond to oxygen.
01:01
This minimizes the formal charge...