00:01
In this problem, we are asked to find the lewis structure of diphosphorus.
00:05
To find the correct lewis structure, we would first need to know how to calculate the formal charge.
00:11
The formal charge is given by the equation the number of valence electrons minus the number of non -bonding electrons, minus the half of the number of bonding electrons.
00:25
The first step to drawing this lewis structure is to figure out the number of valence electron involved, and we know that phosphorus each has five electrons involved, and since there are two phosphorus, this means that there are 10 electrons involved.
00:41
Now, we can start drawing the structure by drawing the two of the phosphors out and connecting them with a single bond.
00:48
Of course, a single bond uses up two electrons, which means that there are eight electrons left.
00:55
We can give the remaining electrons to each of the phosphorus.
01:04
Now, we can try calculating the formal charge, to see whether this loose structure is correct.
01:10
On the right side, we have 5 valence electron minus 6 non -bonding electron minus the half of the bonding electron, which is 2.
01:27
This gives us the formal charge of minus 2, while on the right side it would be 5 minus 2, minus 2 over 2, which would give us positive 2.
01:42
So these two number would be the formal charges of the phosphorus here.
01:47
However, we know that the best lewis structures are the best lewis structures usually have the smallest formal charges as possible, which means that there may be a way to reduce the formal charges here, and we can do that by creating more bonds.
02:09
To create more bonds, we can have one of the lone pairs from the right side and use it to create another bond.
02:17
First, we'll try creating a double bond...