0:00
Okay.
00:01
To determine the lewis structure, you're going to think about the number of valance electrons.
00:06
So as has five valance electrons, one, two, three, four, five.
00:12
And it's paired with three hydrogen.
00:14
And hydrogen, each hydrogen has one valence electron.
00:17
So this is going to look very similar to nh3.
00:20
We're going to connect the ones that are alone.
00:24
And so your structure is going to look like that.
00:27
For part b you have cl and f each one of these has seven valence electrons so if we draw our seven valence electrons you'll notice to make them happy they each need one more so we're going to connect each of their lone ones therefore we can make both happy our last example on this problem is bcl4 minus so boron has three carbon or three bonds excuse me three oh my goodness.
01:07
Three electrons.
01:13
This is the wrong example...