00:01
Okay, here we have a problem that has us to take a particular function, f of x, and put it into standard form, which i have written right here.
00:09
M of x is equal to some constant a times x minus h quantity squared plus k.
00:14
The good thing about that function is that it gives us a vertex very easily as hk.
00:20
Now, what we want to do is look at these first two terms, all the terms involving x, and see if we can get this entire expression here to look like a, perfect square.
00:33
Now the perfect square that begins x squared minus 8x when expanded out is x minus four quantity square, all right? but we have a 21 here whereas that expression has a 16.
00:44
So what we need to do is subtract five from both sides.
00:48
So we've got f of x minus five equals x minus four quantity squared.
00:55
Now all we have to do is add that five back over to the other side of this equation and we've got our standard form.
01:06
Now the vertex is going to be four, five, it's just hk, which means our axis of symmetry is going to be at x equals four.
01:16
And our vertexes are the points where f of x equals zero.
01:20
Now we could take any one of these functions and plug in f of x equals zero.
01:26
So i'm going to take this one because if i take this one, i would just have to take the five back to the other side.
01:32
So i'm going to take negative 5 is equal to x minus 4 quantity squared and unsquared this whole thing...