00:03
Okay, so this question asks us to take a particular function, f of x, and get it into standard form, which looks something like m of x that i have written above.
00:13
So looking at the first two terms of this, x squared plus 12x, the perfect square that comes to mine is x plus 6, quantity squared, but that would have a 36, whereas this has a 40.
00:27
So what we need to do is subtract 4, or better yet, what we can do is x squared plus 12x plus 36 and then we've got that other four there.
00:41
And so this becomes our quantity squared x minus x plus six, excuse me, squared plus four.
00:51
Now our vertex in this case is then negative six, four.
00:55
Recall that in the standard form we have x minus h and so because we have a plus sign here, that means that our h is actually negative 6, which makes our axis of symmetry x equal to negative 6.
01:08
And solving for our intercepts, we can do that quickly.
01:11
That's the point where the value of the function is 0 because it lies on the x -axis...