00:01
Okay, here we have a problem that asks us to take a function of x and get it into a standard form function of the form of m of x that i have written above.
00:11
Now, the first thing we want to do is look at the x squared term.
00:15
We see a negative one there.
00:16
So whenever we see the x squared term multiplied by something, we need to factor that out if you want to get the equation into standard form.
00:25
So let's factor out a negative one equals x squared minus 2x minus 5.
00:32
So all the signs will change.
00:34
Now, we need to get this into the form of a complete square, this section here.
00:42
So x squared minus 2x, that would be x minus 1 squared, right? so if we had x minus 1 quantity squared, we'd have x squared minus 2x plus 1.
00:56
But here we have minus 5.
00:59
So we need to get that to be a plus 1.
01:02
So what i'm going to do is i'm going to add 4.
01:10
What i'm going to do first, actually, is move this negative 1 over.
01:14
I'm going to divide everything by negative 1.
01:17
And so this is negative of x over there.
01:20
And so now we just need to add 4, or excuse me, add 6, if we want positive 1, to both sides.
01:32
So we've got 6 minus f of x over here is equal to x.
01:37
Minus 1.
01:39
Now, all we need to do is move that 6 over and then multiply everything by negative 1 again.
01:46
So i'm going to just erase the 6 from here and then put it on the other side and then put this negative sign.
01:53
All i have to do is remove it from here and put it on this side because that's the same thing as multiplying by negative 1 or dividing by negative 1.
02:00
Either one will work.
02:01
So that's our equation in standard form.
02:03
So we've got that done.
02:04
The good thing about standard form is that it gives us our vertex very easily, because the form v is hk, which means that our axis of symmetry is that x equals 1, and our intercepts are the points where the function takes the value of 0.
02:23
So i'm going to plug in 0 for f of x and just solve...