00:01
Okay, here we have another problem that adds us to take this function f of x and turn it into standard form, which will look something like m of x here.
00:09
So looking at the terms that involve x, the perfect square, when expanded out, that i recognize that i would have this form, is x minus a half quantity squared.
00:22
And so when we do that, we'd have x squared, we'd have two minus a half x terms, which would combine to be the...
00:31
This minus x here.
00:33
And the last term would be a plus one -fourth.
00:37
But what we have is plus five -fourths.
00:40
So i'm going to write this in a slightly different form, x squared minus x, and i'm going to write the plus one -fourth and then plus one, because these two together will equal the five -fourths.
00:53
So i didn't change anything.
00:54
I just wrote in a different way so that we can recognize that this is what we were looking for.
01:00
So x minus one -half quantity squared plus one.
01:06
And now we have our function in standard form.
01:08
The good thing about standard form is that it makes it easy to identify our vertex as hk...