00:01
Okay, this question asks us to take a particular function, in this case, x squared minus 6x, and write it in standard form.
00:08
Now, if you recall, standard form is a function that's quadratic of the form x minus x0 squared plus k, where this x knot and k are just numbers.
00:23
So to get this function in that form, what we're going to do is complete the square.
00:29
So i'm going to add 9 to both sides of this equation.
00:34
What we end up with is f x plus 9 equals x squared minus 6x plus 9.
00:41
Now we know that this here is a perfect career, and it is x minus 3 quantity squared.
00:49
Now all we have to do is move this 9 over.
00:52
So rewritten, what we have is f of x is equal to now x minus 3, quantity squared.
00:59
V squared minus nine.
01:03
Now this question also asks us to sketch the graph and find its intercepts and its vertex.
01:12
So let's sketch the graph.
01:15
Let's take these to be units of three and these to be units of one, which will ultimately give our graph a kind of squished appearance, but it will largely look the same.
01:29
So let's start with x equals 0.
01:31
Well 0 minus 3 is negative 3.
01:33
Negative 3 squared is 9.
01:35
So 9 minus 9 will give us that 0 back.
01:39
So let's take 1.
01:41
1 minus 3 is negative 2.
01:42
Negative 2 squared is 4.
01:45
4 minus 9 is negative 5.
01:49
5...