00:01
All right, in this video, we're looking at evaluating a sum using the sigma notation.
00:06
So in this problem here, we have the sigma symbol, which again means sum of.
00:10
The lower end of the sigma, we have i equal to one.
00:13
That's basically the starting point to our sigma, and the top part of our sigma have a four.
00:17
That's our ending number.
00:19
We also need a, before we find the sum, write out what terms are in the series, and of course, we all can have to find the sum.
00:26
All right.
00:26
So the first thing to do is start plugging in my different values for i, so i can get those terms for the series, and then, of course, i'm going to add them all up.
00:34
Okay, so to find the first term of the series are a subscript 1, we're plugging in 1 for i to start off with, because that's where my stigma starts.
00:42
So this is where my stigma starts.
00:44
This is where it ends.
00:47
All right here, we're placing that with a 1.
00:50
So i have x, subscript 1 to the 3rd, plus 1 ,000 over x, subscript 1 plus 10.
00:58
Now, in the directions to the problem, they told you already what x, subscript whatever number is equal to already.
01:05
In this case, x -subscript 1 is negative 2.
01:08
So x -subscript 1 is negative 2.
01:11
X -substcript 2 is negative 1.
01:15
X -substrip 3 is 0.
01:17
Again, these are in the directions of the problem.
01:20
Make that a little better.
01:23
Okay, and x -subscript 4 is 1.
01:26
They did give you x -subscript 5, but in this question because we're only going up to 4, i don't need to write that one down.
01:30
All right, so where i have x, subscript one, i'll replace that with a negative two, and then i'm just working out that math in my calculation.
01:42
So you just can use a calculator to kind of compute this number out.
01:45
You'll eventually get to a fraction, which can be reduced, and you'll get 124.
01:49
Okay, so that's the first term of the series.
01:51
Okay, to get to the second term, i'm just going in order.
01:53
So i got one, and then x would be two.
01:55
So i got x subscript two to the third...