Question
In Exercises $1-22,$ solve by factoring.$x^{2}-5 x+6=0$
Step 1
We are looking for two numbers that multiply to 6 (the constant term) and add to -5 (the coefficient of the x term). The numbers -2 and -3 satisfy these conditions. So, we can write the equation as $(x-2)(x-3)=0$. Show more…
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