We can use the formula $M_{2} = M_{1} \times \frac{V_{1}}{V_{2}}$ where $M_{1}$ is the initial molarity, $V_{1}$ is the initial volume, and $V_{2}$ is the final volume. Here, $M_{1} = 0.100 \mathrm{M}$, $V_{1} = 50.0 \mathrm{mL}$, and $V_{2} = 100.0 \mathrm{mL}$
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