00:01
This problem wasn't very hard, but it did take a little bit of time.
00:05
Okay.
00:06
So in this problem, you and a lab partner are doing a two -day lab.
00:21
Day one is compositional analysis.
00:35
And day two is melting points.
00:48
You are doing day two.
00:51
Your lab partner does day one.
00:53
So on day two, you go into the lab and you find in your lab drawer or your lab box, two unlabeled vials.
01:13
One vial is a yellow substance, and the other substance is a black powder.
01:37
I'll go back to this.
01:38
You find a note that tells you the compositional analysis.
01:42
You do your melting point, and you find that the melting point for the soft yellow substance is about 25 degrees celsius, and you find that your black powder doesn't melt at all.
01:58
So your apparatus goes up to 1 ,200 degrees and it doesn't melt.
02:05
Your melting point is somewhere greater than 1 ,200 degrees, which indicates that this substance is either ionic or a network solid.
02:20
Those are the only substances that have melting points that high.
02:25
This is most likely molecular.
02:35
Okay.
02:35
Now, so this is a bunch of the information that's given.
02:43
You are also told that compound one, this will be compound one, but we don't know which is which.
02:50
Sorry.
02:52
Compound one has the composition of 70%, 76 .0 % ruthenium and 24 .0 % oxygen.
03:16
Your second substance has a composition of 61 .2 % ruthenium and 38 .8 % oxygen.
03:35
For both of these, you are asked to find the empirical formula.
03:41
So the empirical formula.
03:47
The empirical formula is found by changing percent to mass, which will just be like changing percent to grams, and we'll make the assumption that this is a 100 gram sample for all of these...