00:01
So now we'll work on problem 26 from chapter 17.
00:07
In this problem, we're asked to prepare a ph equals four buffers starting from 1 .5 liters of a 0 .02 molar solution of benzoic acid.
00:21
And any noun we need of sodium benzoate.
00:25
So the first thing they want to know is what is the ph of the benzoic acid solution prior to adding sodium benzodia.
00:34
So first let's go ahead and draw the ka for benzodiazepine.
00:37
And this is equal to 6 .3 times 10 to the minus 5.
00:45
And now we know that benzoic acid is a weak acid, so we can draw an ice table, generic ice table, where the acid reacts with water to form the conjugate base and the hydronium ion.
01:03
So we have an initial value of 0 .0 -2 -00 and no initial acid or hydronium.
01:14
Base or hydronium.
01:17
So we subtract x, add x, add x, and we get 0 .02 minus x, x and x.
01:27
So we set our equilibrium constant equal to x squared divided by 0 .02 minus x...