🎉 Announcing Numerade's $26M Series A, led by IDG Capital!Read how Numerade will revolutionize STEM Learning Numerade Educator ### Problem 46 Easy Difficulty # You are at the controls of a particle accelerator, sending a beam of$1.50 \times 10^{7} \mathrm{m} / \mathrm{s}$protons (mass$m )$at a gas target of an unknown element. Your detector tells you that some protons bounce straight back after a collision with one of the nuclei of the unknown element. All such protons rebound with a speed of$1.20 \times 10^{7} \mathrm{m} / \mathrm{s}$. Assume that the initial speed of the target nucleus is negligible and the collision is elastic. (a) Find the mass of one nucleus of the unknown element. Express your answer in terms of the proton mass$m .(b)$What is the speed of the unknown nucleus immediately after such a collision? ### Answer ## (a)$\overrightarrow{\mathrm{v}}_{g 2}=0.30 \times 10^{7} \mathrm{m} / \mathrm{s}$(b)$m_{g}=9 m\$

#### Topics

Moment, Impulse, and Collisions

### Discussion

You must be signed in to discuss.

Lectures

Join Bootcamp

### Video Transcript

{'transcript': "I have people. This is the problem based on religion off particles. Here it is given the proton is colliding with the nucleus taking in the ship direction off. Brought on as positive direction. So initial velocity your proton one is 1.5 10 to the power seven meter per second. Um, and off Put on too minus one point toe. 10 to the power. Seven meter per second. It polite with the new place. So applying conservation off momentum because no external forces apply acting. It's Yeah. Okay, people is called Pito. Yeah, yeah P evil B B, but p A to baby boom momentum of particles is to find us mass into various is we have a be even m b b. We went I am a veto. Does ambi baby toe say equation? But for elastic region kids Relative velocity before the collision Hello are further Religion must be the same. Yeah, trust me. Solve me part. Okay, be people minus zero. Okay, so are VG. It will You will get be people plus pp two That is 1.5 into 10 to the power seven. 1.2 into 10 to the power seven that is quite 30 10 to the power seven meter per second. So the velocity off nucleus will be after position 13 to 10 to the power seven. No evening equation, but you will get I am in tow. 1.5 into 10 to the power seven plus mass off Nicholas addressed. I am into minus 1.2 into 10 to the power seven, but as empty 0.3 in to 10 to the power seven. So upon solving it marks off. Unknown element will be nine times off him, that's all. Thanks for watching it, okay?"}

Other Schools

#### Topics

Moment, Impulse, and Collisions

Lectures

Join Bootcamp