00:01
Hello and welcome to this video solution of numerate.
00:03
Here you are rearranging the furniture in your living room.
00:06
In doing so you push a 30 kg sofa to the left.
00:11
So the mass of the sofa is 30 kg and you pushed it to the left by a distance of d1 which is 2 meters and to the right by a distance of 1 meter.
00:21
So d2 is 1 meter.
00:24
The coefficient of kinetic friction mu is equal to 0.
00:28
Now a, what is the work done by the friction in moving the sofa? so the work done by friction will be equal to the work done in moving this 2 meters plus work done in moving the 1 meter.
00:40
Now for that what you need is a frictional force.
00:43
Fr is a frictional force times d1 plus the frictional force fr times of d2.
00:49
Because this direction is independent because if you see the work done is scalar.
00:56
So there will be no negative involved here in the work done.
01:03
So the frictional force will be equal to mu times mg and here you will be having d1 plus d2.
01:08
So you plug in the values.
01:09
This is 0 .2.
01:11
The mass is 30.
01:12
G is 9 .8 and this is 1 plus 2 joules...