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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a $0.400-\mathrm{kg}$ ball that is

traveling horizontally at 10.0 $\mathrm{m} / \mathrm{s}$ . Your mass is 70.0 $\mathrm{kg}$ . (a) If you catch the ball, with what speed do you and the ball move after-ward? (b) If the ball hits you and bounces off your chest, so after-ward it is moving horizontally at 8.0 $\mathrm{m} / \mathrm{s}$ in the opposite direction, what is your speed after the collision?

(a) $0.0568 \mathrm{m} / \mathrm{s}$

(b) $0.103 \mathrm{m} / \mathrm{s}$

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{'transcript': "in this question. You're standing on an ice rink and you have the mask 70.0 caveats and your friend throws a zero point for kilograms object of you with a velocity and meet over singing. Now in the case here, you cast the ball and you because off the momentum of the ball, you start moving with velocity. But because you Carter ball the total mass well, now we 70 on four kilograms now the initial warned them before the collision is simply them. Want them off the object that is moving. That's mass, which is the 14 kilograms multiplied by the velocity, which is 10 meters per second. Which is, for it is indeed a president now because you got the ball and they're moving with the Lost City, there is still no force in the horizontal direction, which means more of these cans out on. Hence, the final Wyndham will also before Katie with per second. Now the final went up in this case would be simply master's philosophy, which should be 70.4 kilograms whilst multiply where they were lost. Hence they were lost. We will be 74 divided by 70.4, it's John's out to be 0.5 68 meters per second. Again. Notice that I've used three significant digits because we are giving answers to the numbers in the question. Our three significant digits for five B. The ball bounced off of your chest and is now moving into velocity off eight meters per second and has the same as here upon four kilograms. Now you off the mast. 70 kilograms are moving at a velocity. We now we need to find out the velocity v a. G. You know that the initial Wanda is four kilogram with precision has found out here. And we know that the final order is also equal to the quantum, which is four kilogram meters per second on off. We need to find out the final award of this case now for the person they wanted me simply mass times velocity which is 70 times three. And for the object, the more random is again Master's philosophy. 01 for the mass times velocity, which is eight meters per second. But not that this velocity is in the opposite direction and the velocity will be a minus eight meters per second. So using this equation relight 70 times we is a metaphor less eight times still, 14 would be one 3.2. Hence velocity will be seven point toe divided by Sandy, which turns out to be 0.103 meters per second."}

University of New Mexico