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You are the design engineer in charge of the crashworthiness of new automobile models. Cars are tested by smashing them into fixed, massive barriers at 45 $\mathrm{km} / \mathrm{h} .$ A new model of mass 1500 $\mathrm{kg}$ takes 0.15 s from the time of impact until it is brought to rest. (a) Calculate the average force exerted on the car by the barrier. (b) Calculate the average deceleration of the car.

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Physics 101 Mechanics

Chapter 9

Linear Momentum

Motion Along a Straight Line

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

University of Sheffield

University of Winnipeg

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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Okay, so during Chapter nine, problem 109 So since you're the design engineer in charge of the crashworthiness of new on models, cars are tested by smashing fixed massive barriers at speeds of 40 five kilometers per hour. A new model of mass 1500 kilograms takes a time of view of 15 seconds from the time impact until it is brought to rest. Okay, So calculate the average force exerted on the college five there. Well, the average forces just the change in momentum over the feeding time this is inducted be over two or what goes to rest and a change in velocity is negative. The initial velocity sources 1500 kilograms times negative, 45 kilometers per hour over you report 15 centers. So it's convert this to you for a second one million per second over 3.6 letters per hour and we get an answer of you have won three times 10 years, five years. Cool. And now we can go t um so part be asked, calculate the average deceleration. Well, that's just by Newton's second law. The force divided by the maps so negative 13 times 10 to the five provided by 1500 kilograms gives average deceleration of negative Tedy years for sports Second cool

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