00:01
Hi guys, let's solve the problem 5 .36.
00:05
Here, the problem is we have 357 milliliters of chlorine tri -fluoride gas at 699 millimeter of mercury and at 45 degrees celsius.
00:20
We need to find what is the mass of the sample.
00:25
Let's write down whatever is given.
00:31
We have the volume which is 3 .50.
00:35
We have the pressure which is 699 mm.
00:46
We have the temperature which is 45 degrees.
00:47
We have the temperature which is 45 degrees celsius.
00:54
Now let's convert all the units to the standard unit.
01:00
Therefore the volume should be 357 multiplied by 10 inverse 3 liter.
01:08
The temperature should be 45 plus 273 kelvin which is 318 kelvin and for the pressure we know 760 millimeter of mercury is equal to 1 atm therefore 699 milligram of mercury should be equal to divided by 760 millimeter of mercury it should be equal to 0 .9197.
02:04
Now from ideal gas law we know that pv equal to nrt here n is the number of moles and r is the gas constant so we have the value of p, v, r and t...