00:01
Okay, let's see.
00:03
We have a 1 .0 mole sample.
00:09
It's water and we're at negative 30 .0 degrees celsius.
00:16
We heat until we have gas at 140 degrees c.
00:32
Calculate q for the entire process.
00:41
Okay, this one isn't hard to do and we're given the following.
00:47
We're given our specific heat of ice.
00:51
As 2 .02 j over g degrees c.
01:00
We're given specific heat of liquid water as 4 .18 j over g degrees c.
01:10
We're given specific heat of steam as 2 .02 j over g degrees c.
01:20
We're also given the heat of fusion as 6 .02 kilojoules per motion.
01:28
Mole and the heat of vaporization has 40 .7 kilojoules per mole.
01:41
I'm going to go up here and see if there's anything else on the top of this page.
01:45
No, there we go.
01:48
When i'm doing problems like this, i like to make a plan.
01:52
This is not to scale.
01:54
And this is water, so this is zero degrees c and 100 degrees c.
01:59
We are starting here.
02:02
We're told that we're starting here at negative 30 degrees c.
02:13
And we're going to here to 140 degrees c.
02:17
So we will have one, two, three, four, five steps.
02:29
On this, for steps one, three, and five, we will be using q equals mc delta h.
02:37
For steps 2 and 4, we will be using q equals n delta h.
02:47
And then we'll add them all together.
02:49
I'm going to add these up into kilojoules.
02:51
So i have a one -mole sample.
02:54
Let me make a note that 1 .00 moles of h2o is equal to 18 .02 grams of h2o.
03:07
So here i have my moles and my mass.
03:10
Let's go.
03:13
Step 1, heat ice, and we will be going from minus 30 .0 degrees c to 0 .00 degrees c.
03:26
Thus, my delta t will be, as you can see, 30 .0 degrees celsius.
03:34
Q will equal mass 18 .02 times the specific heat of ice was 2 .02 times my delta...