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Hello everyone.
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Let us see the following question.
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You have a bottle of solid barium hydroxide and some dilute sulfuric acid.
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You place some of the barium hydroxide in water and slowly add some sulfuric acid to the mixture.
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While adding the sulfuric acid, you will measure the conductivity of the mixture.
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So, basically we have barium hydroxide solution.
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So to this barium hydroxide, basically it is a base which is capable of ionizing.
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Into barium ion, b .a .2 plus ion and o .h.
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Minus ion.
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So, to this solution, we slowly add sulfuric acid, that is h2, so4, which also decomposes as 2 h plus ions and sulfate.
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So4, 2 ions.
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So, as the amount of sulfuric acid slowly increases, it starts a neutralizing.
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Neutralization as the neutralization begins the amount of ions in the beaker slowly decreases and hence the conductivity also slowly decreases now based on that we have following questions to be answered question a write the complete balanced equation for the reaction between barium hydroxide b a o h twice, okay, with the sulfuric acid, h2, so4.
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This is a neutralization reaction giving barium sulfate, which is a solid plus two units of water.
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So, hence we have aqueous base and acquiesce acid gives solid precipitate and liquid water.
01:40
This is a neutralization reaction...