Question
You have a cylindrical piece of material $2.4 \mathrm{~cm}$ long and $2.0 \mathrm{~mm}$ in diameter. When you attach a 9-V battery to its ends, a 2.6-mA current flows. Which material from Table $24.1$ do you have?
Step 1
We can use Ohm's law to find the resistance (R) of the material: V = I * R where V is the voltage (9 V) and I is the current (2.6 mA). R = V / I = 9 V / 2.6 mA = 9 V / 0.0026 A = 3461.54 ohms Show more…
Show all steps
Your feedback will help us improve your experience
Mrinal Rana and 99 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A wire is $2.3 \mathrm{m}$ long and has a diameter of $0.38 \mathrm{mm}$. When connected to a $1.2 \mathrm{V}$ battery, there is a current of $0.61 \mathrm{A}$. What material is the wire likely made of?
A cylindrical wire has a length of 2.80 m and a radius of 1.03 mm. It carries a current of 1.35 A, when a voltage of 0.0320 V is applied across the ends of the wire. From what material in Table 20.1 is the wire made?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD