00:01
Okay, so question was asking us to determine the sign of the potential energy.
00:06
So we know electric potential energy is equal to k times q1, q2 over r.
00:10
K is k's k's constant, r is resistant, q1 and q2 is just two different charges.
00:14
So since both q1 and q2 are positive charges, that means the sign of the electric potential energy is positive as well.
00:23
And for question b, it was asking us, what can we do to decrease the potential energy? while we know the electric potential energy is related to 1 over r, which is one of distance, because q1 and q2 was fixed, and k is constant, therefore k is fixed as well.
00:43
So the only changing variable from the equation is r, or not 1 over r.
00:47
So if r change, that means u will change as well.
00:49
And as you can tell, if i increase the distance, which increases the value of r, the value of u, which is the amount of the electric potential energy will decrease as well.
00:58
So if i increase the distance or increase the separation between two charges, the electric potential energy would decrease.
01:07
And for question c, this is the energy bar charge rule...