00:01
So, this question belongs to the laws of thermodynamics in which we have expandable container with moles n equals to 0 .50 moles of oxygen at temperature t equals to 273 kelvin and pressure p equals to 1 atm.
00:16
So for the part a, we have to determine the volume of the gas.
00:19
So from the ideal gas equation that is pv equals to nrt.
00:23
So from here after rearranging volume v, it will be equals to nrt divided by pressure p.
00:28
So, v it will be equals to n which is 0 .50, r which is universal gas constant, so 8 .13 0 .14, jule per mole calvin, temperature t which is 273 kelvin, divided by pressure p, which is 1 atm, so 101 .3, mid -plabit, 10 to the power 3 to convert it into pascal.
00:47
So from here after solving volume v, it is equals to 11 .21 liter.
00:52
So this becomes the answer for the part a of the problem.
00:55
Now, for the part b, we have to calculate if the gas expanded adiabatically twice its volume.
01:03
So, v final is equal to twice of v initial.
01:07
So we have to calculate the final pressure, p final and work done, w.
01:13
So first of all, calculating p final, so from the ideal gas equation, we can write that p final, v final to the power gamma, gamma, that is equal to p initial...