00:01
This is a probability question involving dice.
00:04
And let's start with the first three together, a, b, and c.
00:07
In a, b, and c, we are given a scenario where, for example, you have to get a six on the red dice, a six on the green dice, and a six on the blue dice, or something like that.
00:24
And the question we're being asked is given, is what is the probability of this particular event? happen.
00:32
So what's the probability that we roll a six on the first dice? well, it's one -six.
00:37
Right? what's the probability of multiplying and you are getting a six on the green dice? it's one -sixth.
00:44
And what's the probability of getting a six on the third dice? it's also one -sixth.
00:50
So the probability, and these are independent events.
00:53
This assumes that each dice, each die does not have almost the other dice.
00:57
And so if you do the math, that comes out to be 0 .0 .0 .0.
01:05
046, so a little less than half of a percent.
01:10
Now that's true for all three of these first three questions.
01:16
Each of them are just giving us a scenario where you have a four on the green dice on the three.
01:21
So it's specific roles and the probability that all three of those specific things are going to happen is always just one six times one six times one six.
01:30
Now for d we're giving something different.
01:33
Whereas what's the probability of rolling no sixes at all? well, that means what's the probability of rolling a one through a five? well, the probability on the first day of rolling one, two, three, four, five is five, six.
01:52
There are six sides.
01:53
Five of them are still possibilities.
01:56
The second, for the second die is the same thing.
01:59
What's the probably of not getting six? it's still 5 .6.
02:02
The probability of getting a third ice with no six is still 5 .6...