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Chapter 1, question 69, gives us some information about elements x and y.
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Mass percents for two compounds created with only these two elements, and asks us to determine what those two compounds are and the relative atomic masses of elements x and y.
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So these are the mass percents that they gave us, and these are the two equations that they gave us.
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So let's first look at the equation for components.
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Compound 1 and see if we can figure out whether x or y is diatomic.
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So we have 1x plus 2y, and we know that gives us 2 of our product.
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So let's just combine these first in the simplest way.
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If we just have our product as x y.
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Just at first glance though, we see that this is incorrect.
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We have two y molecules on each side, but but on the left we have 1x and on the right we have 2x.
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We know that we need one more x molecule on the left hand side.
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However, we can't change any of the coefficients here since they were given to us in the problem.
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All that we can do is at a subscript.
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So we know that x is diatomic.
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So this is what we have so far.
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1x2 plus 2y equals 2xy.
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Now let's look at what we have for compound 2.
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We already know that x is diatomic, so we can go ahead and add that in.
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And we know that we have two volumes of our compound.
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So let's once again combine these in the simplest way possible.
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We'll just do x squared or x2 y.
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Now let's see if everything is balanced.
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Again we run into the problem here.
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Our x's are now balanced.
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We have four on each side, but now y isn't.
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We have two y on our product, but only one way in our reactants.
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So we know that y is also diatomic.
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Let's go back to our previous equation and fix that now.
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Now however our y isn't balanced anymore.
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We still have two x on each side, but now we have four y on the left but only two on the right.
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So we know that compound one must have two y molecules in it.
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So now we have our two compounds.
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X, y, two, is compound 1, and x2y is compound 2.
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Now we can bring into play the mass percents.
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So these are the mass percents for each of the two compounds that we were given.
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And we know that this is for x, y, 2, and the bottom set is for x2...