Question

You need the following definition for this exercise: Let $0!=1 ; 1!=1 ; 2!=2 \cdot 1$; and, in general, $n!=n(n-1)(n-2) \cdots 3 \cdot 2 \cdot 1$. The symbol $n!$ is read " $n$ factorial." Now let $$ S_n=2+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\cdots+\frac{1}{n!} $$ Compute $S_n$ for $n=5,10$, and 15 . Compare the resulting values with the value of $e$ on page 424 .

    You need the following definition for this exercise:

Let $0!=1 ; 1!=1 ; 2!=2 \cdot 1$; and, in general, $n!=n(n-1)(n-2) \cdots 3 \cdot 2 \cdot 1$. The symbol $n!$ is read " $n$ factorial." Now let

$$
S_n=2+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\cdots+\frac{1}{n!}
$$


Compute $S_n$ for $n=5,10$, and 15 . Compare the resulting values with the value of $e$ on page 424 .
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Precalculus: A Right Triangle Approach
Precalculus: A Right Triangle Approach
Ratti, McWaters,… 5th Edition
Chapter 4, Problem 112 ↓
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You need the following definition for this exercise: Let $0!=1 ; 1!=1 ; 2!=2 \cdot 1$; and, in general, $n!=n(n-1)(n-2) \cdots 3 \cdot 2 \cdot 1$. The symbol $n!$ is read " $n$ factorial." Now let $$ S_n=2+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\cdots+\frac{1}{n!} $$ Compute $S_n$ for $n=5,10$, and 15 . Compare the resulting values with the value of $e$ on page 424 .
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Transcript

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00:01 So here we have the sum sn is equal to 2 plus 1 over 2 factorial plus 1 over 3 factorial plus up to 1 over n factorial.
00:18 And we want to evaluate that for n is equal to 4, 6, 8, and 10.
00:26 Well, if you do that on your calculator, there is a factorial button in the math menu.
00:38 So use the math button and then go to the probability section.
00:51 And number four is the factorial.
00:55 So you then type in to your calculator for n is 4, 2 plus 1 over 2 factorial plus 1 over 3 factorial plus 1 over 4 factorial.
01:11 And that should give you, let's see here, 2 .7083.
02:01 And then 6 factorial.
02:03 Well, that is going to be s4 plus 1 over 5 factorial plus 1 over 6 factorial...
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