We are given that we have 3.00 mol of $\mathrm{SO}_{3}$ in an 8.00 L flask. So, the initial molarity of $\mathrm{SO}_{3}$ is given by
\[
[\mathrm{SO}_{3}]_{\text{initial}} = \frac{\text{number of moles}}{\text{volume}} = \frac{3.00 \, \text{mol}}{8.00 \, \text{L}}
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