00:01
In the first part of this problem, we are going to calculate the power needed to push the drawer.
00:06
But this power is p.
00:10
Let's define the power in terms of the force as p is equals to f .v.
00:16
Here, this f is the force vector and is the velocity vector.
00:19
And this can be written as fv.
00:22
This will be our equation number one.
00:25
Now, in this case, we have the force as the needed force should be equals to the static fraction.
00:31
And fractional force, and this is equal.
00:33
To mu m g so by inserting this expression for this force into this into the equation number one we can write here p is equals to mu m g v this is our equation number two let's put the values into this equation so it will be p is equals to into 0 .612 into the mass which is equals to at a 4 .5 kg into 9.
01:07
80 meter per second square into the speed which is equal to 0 .3 at 6 meter per second.
01:18
So from here we can write the value for this this p as p is equals to 1905 .6 watt or it can be written as a 1096 watt.
01:36
So this is the answer to the first part of this problem.
01:41
Now let's speak...